parse_url函数在解析url时存在的bug

代码如下：

 <?php
    error_reporting(0);
    require __DIR__."/flag.php";

    $url = urldecode($_SERVER['REQUEST_URI']);
    $url_query = parse_url($url, PHP_URL_QUERY);

    $params = explode("&", $url_query);
    foreach($params as $param){

        $idx_equal = strpos($param, "=");
        if($idx_equal === false){
            $key = $param;
            $value = "";
        }else{
            $key = substr($param, 0, $idx_equal);
            $value = substr($param, $idx_equal + 1);
        }

        if(strpos($key, "do_you_want_flag") !== false || strpos($value, "yes") !== false){
            die("no hack");
        }
    }

    if(isset($_GET['do_you_want_flag']) && $_GET['do_you_want_flag'] == "yes"){
        die($flag);
    }

    highlight_file(__FILE__);